The Binomian Sonnet

In a plus b to the power of n,
be n natural and a and b real,
you can, if you're of Pascal a fan,
the solution quickly reveal.
Start by buildng a sum with k as one
ranging up to n all the way
over following product and you are done
if the math doesn't lead you astray.
n over k you must multiply,
at first by the k-th power of a
and the result of this, without asking why
by b to the power of n minus k.
That is all to say about the Binome,
as with an easy induction was shown.